I might think replicate() is slightly more idiomatic, but I'm not in a position 
to check if simplify=FALSE will keep a list. 

Best,
Michael

On Jun 30, 2012, at 7:13 PM, Rui Barradas <ruipbarra...@sapo.pt> wrote:

> Hello,
> 
> You can avoid the loop using lapply.
> 
> f <- function(x) sample(100, 10)
> samp.list <- lapply(1:20, f)
> 
> will choose 20 samples of 10 integers up to 100 and put them in a list. All 
> you need is to write a function f(). f() must have an argument, even if it 
> doesn't use it. If you need other arguments to be processed by f(), define it 
> and call it as, for instance using the example above,
> 
> f <- function(x, ...) sample(100, 10, ...)
> lapply(1:20, f)  # the same
> lapply(1:20, f, replace=TRUE) # a second argument
> 
> See ?lapply
> 
> Hope this helps,
> 
> Rui Barradas
> 
> Em 30-06-2012 20:34, solafah bh escreveu:
>> Hello
>> I have a loop to sample 20 samples and I want to put them in one list, how I 
>> can make this??
>> 
>> Regards
>> Sulafah
>>    [[alternative HTML version deleted]]
>> 
>> 
>> 
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>> 
> 
> ______________________________________________
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> and provide commented, minimal, self-contained, reproducible code.

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