Hi
I have a follow up question, relating to subsetting to list items. After using 
the list and min(sapply()) method to adjust the length of the variables, 
I specify a dynamic regression equation using the variables in the list. My 
list looks like this:

Dcr<- 
list(Dcre1=DCred1,Dcre2=DCred2,Dcre3=DCred3,Dbobc1=DBoBC1,Dbobc2=DBoBC2,Dbobc3=DBoBC3,...)

By specifying the list items with names, I thought I could end by referencing 
them (or subsetting the list) as, eg., Dcr$Dcre1 and get DCred1, Dcr$Dbobc1 and 
get DBoBC1, etc so that the explanatory variables of the equation can be easily 
associated with their respective original names. This way, I would avoid 
specifying the list as Dcr<-list(Dcr1, Dcr2, Dcr, 3..., Dcr15) and then 
subsetting the list using Dcr[[1]][1:29], Dcr[[[2]][1:29], ..., Dcr[[15]][1:29] 
because the list has many variables (15) and referencing the variables with 
numbers makes them lose their original names.

When I specify the list as Dcr<- list(Dcr1, Dcr2, ..., Dcr15), then the 
regression equation specified as:

# Regression
regCred<- 
lm(Dcr[[1]][1:29]~Dcr[[2]][1:29]+Dcr[[3]][1:29]+Dcr[[4]][1:29]+Dcr[[5]][1:29]+Dcr[[6]][1:29]+...)
runs without problems - the results are shown here below:

Call:
lm(formula = Dcr[[1]][1:29] ~ Dcr[[2]][1:29] + Dcr[[3]][1:29] + 
    Dcr[[4]][1:29] + Dcr[[5]][1:29] + Dcr[[6]][1:29])
Residuals:
    Min      1Q  Median      3Q     Max 
-86.293 -33.586  -9.969  40.147 117.965 
Coefficients:
               Estimate Std. Error t value Pr(>|t|)    
(Intercept)    81.02064   13.28632   6.098 3.21e-06 ***
Dcr[[2]][1:29] -0.97407    0.11081  -8.791 8.20e-09 ***
Dcr[[3]][1:29] -0.27950    0.05899  -4.738 8.95e-05 ***
Dcr[[4]][1:29] -0.07961    0.04856  -1.639    0.115    
Dcr[[5]][1:29] -0.07180    0.05515  -1.302    0.206    
Dcr[[6]][1:29] -0.01562    0.02086  -0.749    0.462    

But when I specify the list with names as shown above, then the equation does 
not run - as shown by the following error message

> # Regression
> regCred<- lm(Dcr[[1]][1:29]~Dcr[[2]][1:29]+Dcr[[3]][1:29]+Dcr[[4]][1:29]+
+ Dcr[[5]][1:29]+Dcr$Dbobc3)
Error in model.frame.default(formula = Dcr[[1]][1:29] ~ Dcr[[2]][1:29] +  : 
  variable lengths differ (found for 'Dcr$Dbobc3')
> Dcr[[5]][1:29]+Dcr$Dbobc3[1:29])
Error: unexpected ')' in "Dcr[[5]][1:29]+Dcr$Dbobc3[1:29])"

NB: In the equation with error message, only the last term is specified by 
referencing its name (ie., Dcr$Dbobc3[1:29]. Also note that the error occurs 
whether I append '[1:29]' to Dcr$Dbobc or not.
How do I resolve this?

Thanks. Lexi


----- Original Message -----
From: "Lekgatlhamang, lexi Setlhare" <lexisetlh...@yahoo.com>
To: Petr PIKAL <petr.pi...@precheza.cz>
Cc: R-Help <r-help@r-project.org>
Sent: Friday, June 29, 2012 1:24 AM
Subject: Re: [R] Adjusting length of series

Thanks a lot Peter. It is a learning process for me.



________________________________
From: Petr PIKAL <petr.pi...@precheza.cz>

Cc: R-Help <r-help@r-project.org> 
Sent: Thursday, June 28, 2012 6:20 PM
Subject: Re: [R] Adjusting length of series
  
Hi

I use R for quite a long time and as I remember I did not use such assign 
paste i loop yet. Insted of such construct with polluting environment with
plenty of objects named something(i)somethingelse it is always advisable 
to use lists.

When you want to shorten variables to some common length (by cutting some 
portion of it) you can do it easily by:

lll<-list(a=1:10, b=1:9, c=1:8)
lll
$a
[1]  1  2  3  4  5  6  7  8  9 10

$b
[1] 1 2 3 4 5 6 7 8 9

$c
[1] 1 2 3 4 5 6 7 8

shortest variable in lll
min(sapply(lll,length))
sapply(lll,"[",1:min( min(sapply(lll,length))))
     a b c
[1,] 1 1 1
[2,] 2 2 2
[3,] 3 3 3
[4,] 4 4 4
[5,] 5 5 5
[6,] 6 6 6
[7,] 7 7 7
[8,] 8 8 8

Regards
Petr


> 
> Dear R Users,
>  
> I ask the following question in order to learn more on the use of 
'assign'
> and 'paste' functions and for loop; otherwise what I am asking could be 
> solved by binding the various first differences of the series using the 
> 'ts.union' operator.
>  
> The problem is:
> I have several variables in my dataset, which I should model dynamically
-
> i.e., with lags of differences of the time series in the regression 
> equation. Consequently, I used a loop (on which I got help from Sarah 
> Goslee) to difference them.
>  
> Using the same variable as in my previous post, the first differences 
are 
> computed as follows:
>  
> > DCred1 <- diff(Cred, difference=1)                     #call this the 
FIRST LOOP
> > for(i in 2:5){
> +   print(assign(paste("DCred", i, sep=""), diff(get(paste("DCred", i-1,
> + sep="")), difference=1)))
> + }
> 
> NB:  I converted the series to time series using 'ts' before 
differencing.
>  
> Now after obtaining first differences, I try to use the 'assign' and 
> 'paste' function in two 'for loops' to adjust the lengths of lagged 
terms 
> (DCred1, DCred2, etc) to have the same length to be used in a regression

> model. My code is:
>  
> for(i in 1:3){                                           #call this the 
SECOND LOOP
> for(j in 3:1){
> print(assign(paste("Dcre", i, sep=""), get(paste("DCred", i, 
sep=""))[j:(136-i)]))
> }
> }
>  
> NB: The length of the original series Cred (before differencing) equals 
> 136. This is why the last term in the assign expression is (136 - i).
> NB: I run this loop after running the first loop which computes the 
first 
> differences, so that the 'get' operator obtains DCred1, DCred2, etc from

> the results of the first loop.
>  
> With this code, I expected to get DCred1 (whose length is 135) and 
> adjust its length to equal that of DCred3 (which is 133) and call the 
> result 'Dcre1'. Similarly, I intended to get DCred2 (whose length is 
134) 
> and adjust its length to 133 (the same as the length of DCred3) and call

> it Dcre2. Lastly, I would get DCred3 of length 133 and call it Dcre3, 
with
> length 133. When I run this code, it runs succesfully. However, when I 
> then check the lengths of Dcre1, ..., Dcre3, I get:
>  
> > length(Dcre1)
> [1] 135
> > length(Dcre2)
> [1] 134
> > length(Dcre3)
> [1] 133
> 
> This shows that my code did NOT achieve the intended outcome.
> Please assist. Thanks.
>  
> Lexi
>    [[alternative HTML version deleted]]
> 
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide 
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
    [[alternative HTML version deleted]]


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