Hello,
You are replacing the values of runif each time through the loop. And
it's not just that, every time through, you are setting outcome[, 1] and
outcome[, 2] to the same values. Simply put, the loop is not needed.
Corrected:
n <- 100 ## patients per trial
trials <- 3 ## 3 trials
med <- as.matrix(c(2,4,3),) ## for example
set.seed(123)
outcome <- matrix(nrow=n*trials, ncol=3)
outcome[, 1] <- rep(1:trials, each=n)
outcome[, 2] <- rep(1:n, trials)
outcome[, 3] <- runif(n*trials, 0, rep(med, each=n))
boxplot(outcome[, 3]~outcome[, 1]) # to see what we have
As you can see from the graph, the medians are now half of the values in
'med'. The name of this variable is misleading, it should be 'maxv' for
maximum value.
I've changed the name of 'median' to 'med', it already is an R function
name. It's misleading for a second reason.
Note also that there is another way of making 'trials' and 'n' vary. It
would change the columns order.
outcome <- expand.grid(1:n, 1:trials) # one instruction.
outcome <- cbind(outcome, runif(n*trials, 0, rep(med, each=n)))
colnames(outcome) <- c("patient", "trial", "value")
Simpler, no?
Hope this helps,
Rui Barradas
Em 27-06-2012 19:01, nqf escreveu:
Dear R-help,
I am writing some simulation code to create multiple sets of time-to-event
clinical trial data (for use in meta-analysis). Within each trial, I want to
apply censoring via simulation of uniform variables (with minimum zero and
maximum the median outcome time for that particular trial).
I have started by pre-allocating a matrix which has 3 columns; one for trial
number, one for patient number, and I want to complete the third with the
results of the uniform simulation.
For example, I have :
n<-10 ## patients per trial
trials<-3 ## 3 trials
outcome<-matrix(NaN,nrow=n*trials,ncol=3)
for(i in 1:trials){
outcome[,1]<-rep(1:trials,each=n)
outcome[,2]<-rep(1:n)
}
In the third column, for each trial I want to create n sets of random draws:
runif(n,0,median[i]), where median[i] is the median outcome time in that
trial.
median<-as.matrix(c(2,4,3),) ## for example
So far I have been trying to include the following within the for loop:
outcome[,3]<-runif(n,0,median[i])
But this just repeats the uniform draws from the last iteration of the loop
in column 3.
Can anyone advise how to replace the third column at each iteration rather
than repeating? I think I can use rbind, but will this slow down my
simulation?
Many thanks in advance for your help.
Natalie
--
View this message in context:
http://r.789695.n4.nabble.com/Replacing-sets-of-rows-in-matrix-within-a-loop-tp4634658.html
Sent from the R help mailing list archive at Nabble.com.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
