Hi James. Yes, you need to identify the namespace in the query, e.g.
getNodeSet(doc, "//x:entry", c(x = "http://www.w3.org/2005/Atom";)) This yeilds 40 matching nodes. (getNodeSet() is more convenient to use when you don't specify a function to apply to the nodes. Also, you don't need xmlRoot(doc), as it works on the entire document with the query "//...".) BTW, you want to use xmlParse() and not xmlTreeParse(). D. On 5/16/12 6:40 PM, J Toll wrote: > Hi, > > I'm trying to use the XML package to read an RSS feed. To get > started, I was trying to use this post as an example: > > http://www.r-bloggers.com/how-to-build-a-dataset-in-r-using-an-rss-feed-or-web-page/ > > I can replicate the beginning section of the post, but when I try to > use another RSS feed I have an issue. The RSS feed I would like to > use is: > >> URL <- >> "http://www.sec.gov/cgi-bin/browse-edgar?action=getcurrent&type=&company=&dateb=&owner=include&start=0&count=40&output=atom"; > >> library(XML) >> doc <- xmlTreeParse(URL) > >> src <- xpathApply(xmlRoot(doc), "//entry") > > I get an empty list rather than a list of each of the "entry": > >> src > list() > attr(,"class") > [1] "XMLNodeSet" > > I'm not sure how to fix this. Any suggestions? Do I need to provide > a namespace, or is the RSS malformed? > > Thanks, > > > James > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
