I'm curious about the 'real' answer myself but this would work:
ls(pattern='^d')[ls(pattern='^d') %in% ls(pattern='[[:digit:]]$')] Cheers,Tyler Rinker ---------------------------------------- > Date: Fri, 11 May 2012 13:18:59 -0500 > From: jun.shen...@gmail.com > To: r-h...@stat.math.ethz.ch > Subject: [R] How to specify multiple regular expressions for pattern argument > > Dear list, > > I want to show all the objects starting with "d" and ending with a digit. > How do I specify these conditions in the pattern argument > > I can do one condition but not two > > ls(pattern='^d') > ls(pattern='[[:digit:]]$') > > are working. > > But, > > ls(pattern='^d'&'[[:digit:]]$') is not working. > > Appreciate any comment. > > Jun Shen > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
