On May 8, 2012, at 4:35 AM, Suhaila Haji Mohd Hussin wrote:
> Hello.
>
> Sorry if that's considered laziness as I've just learnt R and didn't
> know how important it is to do dput for all problems.
>
> If I was truly lazy then I wouldn't even bother to sign up here and
> ask questions.
>
> Please be nicer next time.
>
> Suhaila.
>
> > CC: r-help@r-project.org
> > From: dwinsem...@comcast.net
> > To: bell_beaut...@hotmail.com
> > Subject: Re: [R] Problem with Median
>
> > Date: Mon, 7 May 2012 20:25:24 -0400
> >
> >
> > On May 7, 2012, at 5:16 PM, Suhaila Haji Mohd Hussin wrote:
> >
> > >
> > > Hello.
> > > Now the median is solved but then I'm still figuring out how to
> put
> > > the updated column back to replace the original column of the
> whole
> > > data. I'll show you what I meant:
> > > Continuing from the previous commands you guys helped out I
> > > continued as followed:
> > > Original Data:
> > > http://i1165.photobucket.com/albums/q585/halfpirate/data.jpg
> > >
> > > Before column a: http://i1165.photobucket.com/albums/q585/halfpirate/1.jpg
> >
> > That fine for sending pictures to the family but NOT for
> communicating
> > R code.
> > >
> > > 1) a.AC [is.na(a.AC)] <- median(a.AC$a, na.rm= TRUE)
> > > 2) a.ACAfter column a:
> > > http://i1165.photobucket.com/albums/q585/halfpirate/2.jpg
> > > 3) data$a <- a.ACGives me error that the original data has 6 rows
> > > yet the one I'm replacing is 1 row.
> > > I understand the error and I don't want to completely replace the
> > > column if I really want to.
> >
> > You were not attempting to replace the entire column, but you were
> > trying to replace 6 entries. So why not... :
> >
> > a.AC [is.na(a.AC)] <- rep( median(a.AC$a, na.rm= TRUE) , 6)
> >
> >
> > > Basically I'm expecting the result to be like this. After you
> > > compare the original data, the final answer should be like
> > > thishttp://i1165.photobucket.com/albums/q585/halfpirate/3.jpg
> >
> > What part of "I can't do anything with your jpeg to answer your
> > questions about your dataframe" was difficult to understand? We do
> NOT
> > want pictures from which we need to repeat data entry that you have
> > already done. The first virtue of a programmer being laziness.
> > Console output is also very ambiguous. Learn to use str() and dput()
> > or dump().
> >
> > ?dput
> > ?dump
> >
> > And run the examples. please.
> >
> > --
> > David.
> >
> >
> > > Please help.Suhaila
> > > From: bell_beaut...@hotmail.com
> > > To: jholt...@gmail.com
> > > CC: r-help@r-project.org
> > > Subject: RE: [R] Problem with Median
> > > Date: Tue, 8 May 2012 07:22:19 +1200
> > >
> > > Thank you so much!
> > > Suhaila.
> > >
> > >> Date: Mon, 7 May 2012 15:08:47 -0400
> > >> Subject: Re: [R] Problem with Median
> > >> From: jholt...@gmail.com
> > >> To: bell_beaut...@hotmail.com
> > >>
> > >> Your problem is that a.AC is a dataframe:
> > >>
> > >>
> > >>> x <- read.table(text = " a b c class
> > >> + 1 12 0 90 A-B
> > >> + 2 3 97 11 A-B
> > >> + 3 78 NA 123 A-C
> > >> + 4 NA NA 12 A-C
> > >> + 5 8 33 2 A-B
> > >> + 6 12 NA 0 A-D", header = TRUE)
> > >>> a.AC <- subset(x, class == "A-C", select = a)
> > >>> # same error
> > >>> median(a.AC)
> > >> Error in median.default(a.AC) : need numeric data
> > >>
> > >>> # now look a the structure of a.AC (its a dataframe)
> > >>> str(a.AC)
> > >> 'data.frame': 2 obs. of 1 variable:
> > >> $ a: int 78 NA
> > >>> # now do it right
> > >>> median(a.AC$a)
> > >> [1] NA
> > >>> median(a.AC$a, na.rm = TRUE)
> > >> [1] 78
> > >>
> > >>
> > >>
> > >> On Mon, May 7, 2012 at 2:52 PM, Suhaila Haji Mohd Hussin
> > >> <bell_beaut...@hotmail.com> wrote:
> > >>>
> > >>> Hello.
> > >>> I'm trying to compute median for a filtered column based on
> other
> > >>> column but there was something wrong. I'll show how I did step
> by
> > >>> step.
> > >>> Here's the data:
> > >>> a b c class
> > >>>
> > >>> 1 12 0 90 A-B2 3 97 11 A-B3 78 NA
> > >>> 123 A-C4 NA NA 12 A-C5 8 33 2 A-B6
> > >>> 12 NA 0 A-D
> > >>> On the command I typed:
> > >>> 1) data = read.csv("data.csv")
> > >>>
> > >>> 2) a.AC <- subset(data, class == "A-C", select = a)
> > >>> 3) median(a.AC)Error in median.default(a.AC) : need numeric data
> > >>> 4) is.numeric(a.AC)FALSE
> > >>> 5) as.numeric(a.AC)Error: (list) object cannot be coerced to
> type
> > >>> 'double'
> > >>> How can I fix this? Please help.
> > >>> Cheers,Suhaila
> > >>> [[alternative HTML version deleted]]
> > >>>
> > >>> ______________________________________________
> > >>> R-help@r-project.org mailing list
> > >>> https://stat.ethz.ch/mailman/listinfo/r-help
> > >>> PLEASE do read the posting guide
> > >>> http://www.R-project.org/posting-guide.html
> > >>> and provide commented, minimal, self-contained, reproducible
> code.
> > >>
> > >>
> > >>
> > >> --
> > >> Jim Holtman
> > >> Data Munger Guru
> > >>
> > >> What is the problem that you are trying to solve?
> > >> Tell me what you want to do, not how you want to do it.
> > >
> > >
> > > I might be silly but if I was going to type in dput() then how
> > > should I send the data over here?
> > > Instead, I've just uploaded the image online, you can access it
> via
> > > the link below.
> > > http://i1165.photobucket.com/albums/q585/halfpirate/data.jpg
> > >
> > >> Date: Mon, 7 May 2012 14:55:24 -0400
> > >> Subject: Re: [R] Problem with Median
> > >> From: sarah.gos...@gmail.com
> > >> To: bell_beaut...@hotmail.com
> > >> CC: r-help@r-project.org
> > >>
> > >> Please use dput() to give us your data (eg dput(data) ) rather
> than
> > >> simply pasting it in.
> > >>
> > >> Sarah
> > >>
> > >> On Mon, May 7, 2012 at 2:52 PM, Suhaila Haji Mohd Hussin
> > >> <bell_beaut...@hotmail.com> wrote:
> > >>>
> > >>> Hello.
> > >>> I'm trying to compute median for a filtered column based on
> other
> > >>> column but there was something wrong. I'll show how I did step
> by
> > >>> step.
> > >>> Here's the data:
> > >>> a b c class
> > >>>
> > >>> 1 12 0 90 A-B2 3 97 11 A-B3 78 NA
> > >>> 123 A-C4 NA NA 12 A-C5 8 33 2 A-B6
> > >>> 12 NA 0 A-D
> > >>> On the command I typed:
> > >>> 1) data = read.csv("data.csv")
> > >>>
> > >>> 2) a.AC <- subset(data, class == "A-C", select = a)
> > >>> 3) median(a.AC)Error in median.default(a.AC) : need numeric data
> > >>> 4) is.numeric(a.AC)FALSE
> > >>> 5) as.numeric(a.AC)Error: (list) object cannot be coerced to
> type
> > >>> 'double'
> > >>> How can I fix this? Please help.
> > >>> Cheers,Suhaila
> > >>
> > >>
> > >> --
> > >> Sarah Goslee
> > >> http://www.functionaldiversity.org
> > >
> > >
> > > [[alternative HTML version deleted]]
> > >
> > > ______________________________________________
> > > R-help@r-project.org mailing list
> > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > PLEASE do read the posting guide
> > > http://www.R-project.org/posting-guide.html
> > > and provide commented, minimal, self-contained, reproducible code.
> >
> > David Winsemius, MD
> > West Hartford, CT
> >
David Winsemius, MD
West Hartford, CT
[[alternative HTML version deleted]]
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