Hi, is there an elegant way to use 'substitute' with '...' arguments?
My first try was this: > f1 <- function(...) substitute(...) > f1( 2+7, "foo", 3+5 ) 2 + 7 As you can see, substitute acts only on the first argument. So I tried > f2 <- function(...) substitute(list(...)) > f2( 2+7, "foo", 3+5 ) list(2 + 7, "foo", 3 + 5) This is now all the information I want, but it is not split into the individual arguments. I would like to get a character vector, i.e. something like c( "2 + 7", "\"foo\"", "3 + 5" ) My third try seems to be wrong as well: > f3 <- function(...) lapply( list(...), substitute ) > f3( 2+7, "foo", 3+5 ) Error in lapply(list(...), substitute) : '...' used in an incorrect context Does anybody has a good hint for me as how to do it correctly? Thanks Simon +--- | Dr. Simon Anders, Dipl. Phys. | European Bioinformatics Institute, Hinxton, Cambridgeshire, UK | preferred (permanent) e-mail: [EMAIL PROTECTED] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
