Thank you so much!
Suhaila.
> Date: Mon, 7 May 2012 15:08:47 -0400
> Subject: Re: [R] Problem with Median
> From: jholt...@gmail.com
> To: bell_beaut...@hotmail.com
>
> Your problem is that a.AC is a dataframe:
>
>
> > x <- read.table(text = " a b c class
> + 1 12 0 90 A-B
> + 2 3 97 11 A-B
> + 3 78 NA 123 A-C
> + 4 NA NA 12 A-C
> + 5 8 33 2 A-B
> + 6 12 NA 0 A-D", header = TRUE)
> > a.AC <- subset(x, class == "A-C", select = a)
> > # same error
> > median(a.AC)
> Error in median.default(a.AC) : need numeric data
>
> > # now look a the structure of a.AC (its a dataframe)
> > str(a.AC)
> 'data.frame': 2 obs. of 1 variable:
> $ a: int 78 NA
> > # now do it right
> > median(a.AC$a)
> [1] NA
> > median(a.AC$a, na.rm = TRUE)
> [1] 78
>
>
>
> On Mon, May 7, 2012 at 2:52 PM, Suhaila Haji Mohd Hussin
> <bell_beaut...@hotmail.com> wrote:
> >
> > Hello.
> > I'm trying to compute median for a filtered column based on other column
> > but there was something wrong. I'll show how I did step by step.
> > Here's the data:
> > a b c class
> >
> > 1 12 0 90 A-B2 3 97 11 A-B3 78 NA 123
> > A-C4 NA NA 12 A-C5 8 33 2 A-B6 12 NA 0
> > A-D
> > On the command I typed:
> > 1) data = read.csv("data.csv")
> >
> > 2) a.AC <- subset(data, class == "A-C", select = a)
> > 3) median(a.AC)Error in median.default(a.AC) : need numeric data
> > 4) is.numeric(a.AC)FALSE
> > 5) as.numeric(a.AC)Error: (list) object cannot be coerced to type 'double'
> > How can I fix this? Please help.
> > Cheers,Suhaila
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
>
>
>
> --
> Jim Holtman
> Data Munger Guru
>
> What is the problem that you are trying to solve?
> Tell me what you want to do, not how you want to do it.
[[alternative HTML version deleted]]
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