Hello, I'm using fArma package to estimate the value of Hurst exponent using R/S method. However, for a certain set of data I get H ~ 1.8. How do I interpret this?
Following are the output that I get for this set: > mean(data[,2]) [1] 400.5433 > sd(data[,2]) [1] 1139.786 > > rsFit(data[,2], levels = 64) Title: Hurst Exponent from R/S Method Call: rsFit(x = data[, 2], levels = 64) Method: R/S Method Hurst Exponent: H beta *1.826240 1.826240 * Hurst Exponent Diagnostic: Estimate Std.Err t-value Pr(>|t|) X 1.826240 3.352896 0.5446755 0.5919988 Parameter Settings: n levels minnpts cut.off1 cut.off2 11895 64 3 5 316 Description: Mon May 7 16:16:59 2012 by user: Warning messages: 1: In rsFit(data[, 2], levels = 64) : Integer overflow in 'cumsum'; use 'cumsum(as.numeric(.))' 2: In (1:m) * Y[m] : NAs produced by integer overflow 3: In (1:m) * Y[m] : NAs produced by integer overflow 4: In (1:m) * Y[m] : NAs produced by integer overflow 5: In (1:m) * Y[m] : NAs produced by integer overflow 6: In lsfit(log10(M), log10(RS), wt) : 37 missing values deleted > -- Thanks, Barun Saha JPA IIT, Kharagpur http://pothi.com/pothi/book/barun-saha-swapner-kheya http://delay-tolerant-networks.blogspot.com/p/one-tutorial.html [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.