Thank you very much, though I still don't quite undertdand the explanation :)
Nevertheless, I just found a seemingly simple (at least quiker to type)
solution after try-and-error:
eval(mapply(function(x) {x; function() x}, c("a", "b")))
Wish it may help future readers.
On Thu, May 03, 2012 at 04:18:38PM +0200, Jessica Streicher wrote:
> So, to get back to mapply:
>
> eval(mapply(function(x) substitute(function() z,list(z=x)), c("a", "b"))$a)()
> or like this:
> mapply(function(x) eval(substitute(function(i) z*i,list(z=x))),
> c(2,3))[[1]](2)
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