for (n in LIST2) print(as.character(n))
[1] "Michael"
[1] "Dana"
[1] "Rob"

Eloi

On 12-04-24 12:22 PM, R. Michael Weylandt wrote:
Don't you just want

LIST<- as.data.frame(LIST, stringsAsFactors = FALSE) # Avoid making factors

for(n in LIST) print(n)

But I can't understand why you want to do it this way.... I'll presume
this makes more sense in your application.

On Tue, Apr 24, 2012 at 2:29 PM, michaelyb<cel81009...@gmail.com>  wrote:
Hello All!

I need some help to get a FOR LOOP to print the interactor with the
quotation mark.

Let me be more specific:

I have the following:
cbind("Michael","Dana","Rob")->LIST

outcome:
     [,1]      [,2]   [,3]
[1,] "Michael" "Dana" "Rob"

UNFORTUNATELY, I need to do the following:
as.data.frame.list(LIST)->LIST2
rm(LIST)

outcome:
  X.Michael. X.Dana. X.Rob.
1    Michael    Dana    Rob

My problem:
I tried the following LOOP:
for (n in LIST2)print((paste("\'",n,"\'"))

outcome:
[1] "*'* Michael *'*"
[1] "*'* Dana*'*"
[1] "*'* Rob*'*"

How can I get the following instead:
[1] "Michael"
[1] "Dana"
[1] "Rob"

Detail: I cannot use the first LIST to do the FOR LOOP since I need to
remove it first.
Any help, please?

Thank you!

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--
Eloi Mercier
Bioinformatics PhD Student, UBC
Paul Pavlidis Lab
2185 East Mall
University of British Columbia
Vancouver BC V6T1Z4

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