I'm not sure I follow exactly what group of regression models you want to
create, but a good first step might be to use reshape so that each party's
vote share goes on a different row and the vote shares are all in the same
column. Then you can use plyr grouping on tipo and party to make your
models...

library(reshape2)
library(plyr)

ast <- melt(asturias.gen2011, id=c("municipio", "total", "tipo"),
variable.name="party", value.name="vote")

dlply(ast, .(party, tipo), lm, formula=vote~total)

or along those lines. This way you don't have to mess around with pasting
together expressions to eval and so on...

Peter

On Sun, Mar 18, 2012 at 12:59 PM, Igor Sosa Mayor <
joseleopoldo1...@gmail.com> wrote:

> Hi,
>
> I have a dataframe basically like this:
>
> > head(asturias.gen2011[,c(1,4,9:14)])
>               municipio total upyd  psoe    pp    iu   fac        tipo
> 440              Allande  2031 1.44 31.10 39.75  4.01 21.62  1000-10000
> 443                Aller 12582 1.37 33.30 37.09 15.53 10.35 10000-50000
> 567               Amieva   805 1.48 32.69 37.36  6.15 20.16       <1000
> 849               Avilés 84202 4.15 30.26 35.49 14.37 11.80      >50000
> 1087 Belmonte de Miranda  1751 1.66 38.42 35.74  7.22 14.81  1000-10000
> 1260             Bimenes  1894 0.98 34.28 26.87 23.30 10.98  1000-10000
>
> I want to do the following:
> 1. for every party (psoe, pp, etc.) I want to create a variable like
> this: upyd.lm.tipos, psoe.lm.tipos, etc.
>
> 2. I want to store in this variable a regression (psoe~total), but
> split up by tipo.
>
> I have the main idea of using dlply from the plyr vignette. But when I
> try to put all this in a loop I'm coming into trouble and I'm at the
> moment really confused how to solve this problem:
>
> I have the following function:
>
> elecregtipos <- function(y){
>    z<-dlply(asturias.gen2011, .(tipo), function(x) lm(x[,y]~x$edad.media))
>    # rsq<-function(x) summary(x)$r.squared
>    # bcoefs<-ldply(z, function(x) c(coef(x), rsquare=rsq(x)))
>    #  return (bcoefs)
>    return(z)
> }
>
> And I try to call it with:
> for (y in c("upyd", "psoe", "pp", "fac", "iu")) {
>  eval(parse(text=paste(y,'.lm.tipos', '<- elecregtipos(',y,')',sep='')))
> }
>
> At the moment I'm getting the error:
> Error en `[.data.frame`(x, , y) : objeto 'upyd' no encontrado
>
> If I call simply:
> elecregtipos("upyd")
>
> it works perfectly. The problem is the loop, column names, etc., but I'm
> really confused what I still could try, because I have already tried any
> possibility.
>
> Any hint?
>
> Thanks in advance.
>
>
> --
> :: Igor Sosa Mayor     :: joseleopoldo1...@gmail.com ::
> :: GnuPG: 0x1C1E2890   :: http://www.gnupg.org/      ::
> :: jabberid: rogorido  ::                            ::
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>

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