On Sun, Mar 18, 2012 at 09:43:54PM +0000, Dajiang Liu wrote: > > Dear All, > I have a seemingly very simple question, but I just cannot figure out the > answer. I attempted to run the following:a=0.1*(1:9);which(a==0.3);it returns > integer(0). But obviously, the third element of a is equal to 0.3. > I must have missed something. Can someone kindly explain why? Thanks a lot.
Hi. A simple way to detect rounding problems is subtracting the numbers. a = 0.1*(1:4) a - 0.3 [1] -2.000000e-01 -1.000000e-01 5.551115e-17 1.000000e-01 Use rounding to avoid it as suggested by others. Petr Savicky. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
