Col3 <- unique(Msg17$V3)
LCol3 <- length(Col3)
for (i in 1:LCol3) {
print(paste("Column", Col3[i]))
write.table(Msg17[Msg17$V3==Col3[i],-3], row.names=F, col.names=F,quote=F)
# If you R implementation does not accept 'F', use 'FALSE'
}
--
View this message in context:
http://r.789695.n4.nabble.com/Output-formatting-in-Latex-and-R-tp4483631p4483863.html
Sent from the R help mailing list archive at Nabble.com.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
