df$x is list so you have to use this type of assignment
> df$x[[1]] <- c('a','b')
> df
y x
1 1 a, b
2 1 f, c
3 1 a
> df$x[[3]] <- letters
> df
y x
1 1 a, b
2 1 f, c
3 1 a, b, c,....
> str(df)
'data.frame': 3 obs. of 2 variables:
$ y: num 1 1 1
$ x:List of 3
..$ : chr "a" "b"
..$ : chr "f" "c"
..$ : chr "a" "b" "c" "d" ...
..- attr(*, "class")= chr "AsIs"
>
On Thu, Mar 27, 2008 at 4:27 PM, Daniel E. Bunker <[EMAIL PROTECTED]> wrote:
> Hi All,
>
> I need to place lists or vectors within dataframes as single
> elements. However when I try this:
>
> df=data.frame(y=1, x=I(list(c("a","b"), c("f","c"), c("a"))))
> df
>
> df[1,'x']=I(c("a","d"))
>
> I get this error, even though I am using I():
>
> Error in `[<-.data.frame`(`*tmp*`, 1, "x", value = c("a", "d")) :
> replacement has 2 rows, data has 1
>
> Note that this behavior does not match that described here <http://
> finzi.psych.upenn.edu/R/Rhelp02a/archive/37297.html> in this post
> from 2004.
>
> Can someone please point me towards the right way to do this?
>
> Thanks!!
>
> Dan
>
>
>
> $platform
> [1] "i386-apple-darwin8.10.1"
>
> $arch
> [1] "i386"
>
> $os
> [1] "darwin8.10.1"
>
> $system
> [1] "i386, darwin8.10.1"
>
> $status
> [1] ""
>
> $major
> [1] "2"
>
> $minor
> [1] "6.2"
>
> $year
> [1] "2008"
>
> $month
> [1] "02"
>
> $day
> [1] "08"
>
> $`svn rev`
> [1] "44383"
>
> $language
> [1] "R"
>
> $version.string
> [1] "R version 2.6.2 (2008-02-08)"
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem you are trying to solve?
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