Hello, "uday", e.g.,
(data - 1) %/% 3 + 1 would do the job in your very specific situation, but take a look at ?findInterval for possibly more interesting (because more general) solutions. Hth -- Gerrit On Tue, 13 Mar 2012, uday wrote:
I want to replace some values in my Array e.g data<- c(1,2,3,4,5,6,7,8,9,10,11,12) I would like to replace 1,2,3 by 1 , 4,5,6 by 2, 7,8,9 by 3 and 10,11,12 by 4 I am expecting out put data<- 1 1 1 2 2 2 3 3 3 4 4 4 I have tried replace function replace(data, (data==1 |data==2| data==3),1) replace(data, (data==4|data==5| data==6),2) replace(data, (data==7|data==8| data==9),3) replace(data, (data==10 |data==11| data==12),4) but it changes only for individual operation it does not apply to whole array. So how I should replace values of whole array ? -- View this message in context: http://r.789695.n4.nabble.com/replacing-values-in-Array-tp4468739p4468739.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
