You could make a vector containing the number of TRUE values that makes up 80% of your data, and the number of FALSE values that makes up 20% of your data. Use sample() to reorder it, then use it to divide your dataset.
If you had provided a reproducible example, I could write you code. Sarah On Wed, Mar 7, 2012 at 11:41 AM, Oritteropus <lucasantin...@hotmail.com> wrote: > Hi, > I need to sample randomly my dataset for 1000 times. The sample need to be > the 80%. I know how to do that, my problem is that not only I need the 80%, > but I also need the corresponding 20% each time. Is there any way to do > that? > Alternatively, I was thinking to something like setdiff () function to > compare my 80% sample to the original dataset and obtain the corresponding > 20%, unfortunately setdiff works just for vectors, do you know a similar > function for dataframes? > Thanks > -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
