I know this is something simple that I cannot do because I do not yet "think"
in R.
I have a data frame has a variable participation (a factor), and several
other factors.
I want a chisq test (no contingency tables) for participation vs all of the
other factors.
In SPSS I would do:
CROSSTABS
/TABLES= (my other factors) BY participation
/FORMAT=NOTABLES
/STATISTICS=CHISQ
/COUNT ROUND CELL.
In R I have tried something like:
mapply(chisq.test,participation,surv3[,names(surv3) %in% c('q10','q44')])
which should be effectively the same as
chisq.test(participation,q10)
chisq.test(participation,q44)
except maybe I could store the results better....
but I get told that x and y are not the same length, and in this case,
length() of the y argument is 2, which yes, is not the number of rows in the
data frame.
I'm not sure that it is mapply, rather than lapply that I want
Thanks,
Jon
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