A reproducible example would be helpful, but lacking that here's some untested code. If your data frame has NA values, those will also need to be dealt with.
apply(mydata, 1, function(x)sum(x != 0)) Sarah On Tue, Mar 6, 2012 at 12:03 PM, mari681 <marianna.bologn...@gmail.com> wrote: > I feel this is a very easy thing but I've never done it before and it is > getting frustrating. > I have a big data.frame (1445846 rows, 15 col) > that looks like this: > > V1 V2 V3 V4 V5 > > 1 home sister brother chair 0 > 2 cat dog animal 0 0 > 3 girl boy 0 0 0 > 4 knife fork spoon 0 0 > > and I want to count how many values different from 0 are in each row, and > get the output count in a vector that is as long as length(MyTable). For the > above example it would be c (4,3,2,3). > I've tried sum (MyTable != "0") but it gives the total amount of values > different from 0 in all the data.frame. > And sum(MyTable [1,] != "0") obviously gives only the first row, even if I > repeat it throughout all length(MyTable). > How does that work? > > Thank you, > > a newbie. > > -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
