Hello,
pavlo wrote > > I have an array > l <- c(1,1,1,1, 0,0,0,0,0, 1,1,1,1,1,1) > > I would like to get a rugged array > [[1]] 1,1,1,1 > [[2]] 0,0,0,0,0 > [[3]] 1,1,1,1,1,1 > > catching every group of contiguous repeated values. Any help would be > greatly appreciated! > -Pavel > Is this it? x <- c(1,1,1,1, 0,0,0,0,0, 1,1,1,1,1,1) contig <- cumsum(abs(diff(c(x[1], x)))) split(x, contig) Hope this helps, Rui Barradas -- View this message in context: http://r.789695.n4.nabble.com/split-array-into-groups-by-value-tp4448578p4448622.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
