On Mar 1, 2012, at 2:40 PM, Dennis Fisher wrote:
R 2.14.0
OS X
Marc's proposed solution (appearing at the end of this email) is
perfect -- thanks so much
However, some questions remain:
1. The following works:
plot(1, type="n")
text(1, 1, expression(symbol("\342")))
but this does not work (TEXT appears in a symbol font)
plot(1, type="n")
TEXT <- "\342"
text(1, 1, expression(symbol(TEXT)))
?substitute
text(1, 1, substitute( symbol(TEXT), list(TEXT=TEXT) ) )
?bquote
text(1, 1, bquote( symbol( .(TEXT ) ) ) )
nor does this work (it yields: Error: could not find function
"symbol")
plot(1, type="n")
TEXT <- symbol("\342")
text(1, 1, expression(TEXT))
Clearly, I do not understand the subtleties of plotmath.
expression() does not evaluate names within its arguments. Similar
issues arise with the use of "$" as a function. That's why it's often
the answer to programming questions that one should use obj[[colnam]]
than it is to use obj$colnam. "[[" does evaluate its argument.
Could someone explain?
Try instead:
plot(1, type="n")
TEXT <- expression(symbol("\342"))
text(1, 1, TEXT)
If you want to build up from character-type components then you can
use paste and wrap the whole think in as.expression(). bquote() is
much better, though.
--
David.
2. How would one learn that \342 corresponds to the copyright sign
in the symbol font? (i.e., is there a list of all possible characters)
Dennis Fisher MD
P < (The "P Less Than" Company)
Phone: 1-866-PLessThan (1-866-753-7784)
Fax: 1-866-PLessThan (1-866-753-7784)
www.PLessThan.com
On Feb 29, 2012, at 6:55 PM, Marc Schwartz wrote:
Dennis,
Depending upon some additional fine tuning, here is a generic
example:
plot(1)
legend("topright", pch = 1, legend = expression(SOMETEXT ^
symbol("\342")))
See ?plotmath for more information. The above works on my MBP
running Lion.
HTH,
Marc Schwartz
[[alternative HTML version deleted]]
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David Winsemius, MD
West Hartford, CT
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