Maybe: xyplot(values ~ ind|ind, data = stack(split(m, 1:4)))
On 24/03/2008, Ron Bonner <[EMAIL PROTECTED]> wrote: > Sorry if this is an FAQ, but I haven't found the answer (yet)... > > I'm trying to plot each row of a simple numeric matrix in a separate > panel using the layout features of lattice, but can't make it work - > help would be appreciated! > > Example: > > > m <- matrix(seq(1:20), nrow=4) > > > m > [,1] [,2] [,3] [,4] [,5] > [1,] 1 5 9 13 17 > [2,] 2 6 10 14 18 > [3,] 3 7 11 15 19 > [4,] 4 8 12 16 20 > > The following will plot one row in one box: > > > xyplot(m[1,] ~ seq(1:5)) > > but this gives all rows in the same box: > > > xyplot(m ~ seq(1:5)) > > Since there are no factors, how can I set conditioning variable to get > what I want, or is there a better way to do this? > > Thanks in advance > > Ron > > Ron Bonner > [EMAIL PROTECTED] > skype: rbonners > > > > > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.