try this:
file_s <- list.files(path = ".", pattern = "v2.0.2.txt", all.files = FALSE,
full.names = FALSE, recursive = FALSE,
ignore.case = FALSE)
result <- do.call(rbind, lapply(file_s, function(.file){
data <- read.table(.file, header=TRUE)
data.frame(lat = data[,7] # latitude
, lon = data[,8] # longitude
, gas = data[,45] # gas
, time.s = data[,5] # time
, stringsAsFactors = FALSE
)
}))
On Tue, Feb 14, 2012 at 5:07 AM, uday <uday_143...@hotmail.com> wrote:
> I have some data files e.g 100 . and after for loop I would like to save all
> data in one single data frame
>
> file_s <- list.files(path = ".", pattern = "v2.0.2.txt", all.files = FALSE,
> full.names = FALSE, recursive = FALSE,
> ignore.case = FALSE)
> for (i in 1:100){
> data = read.table(file_s[i],header=TRUE)
> lat = data[,7] # latitude
> lon = data[,8] # longitude
> gas = data[,45] # gas
> time.s = data[,5] # time
> }
>
> How I should get all these 100 files variable in to single data frame ?
>
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/save-output-of-loop-tp4386599p4386599.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
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