Seems fine to me: exp(pi + i*2pi) = exp(pi) * exp(i *2pi) = exp(pi) * (cos(2pi) + i*sin(2*pi)) = exp(pi) *(1+ 0i) = exp(pi) ~ 23.14 exp(pi/2) ~ 4.81
What would you expect? Michael On Mon, Jan 30, 2012 at 10:37 AM, Joseph Park <josephp...@ieee.org> wrote: > Hi, > > Am i doing something silly here in expecting Euler's > formula to be handled by exp? exp( ix ) = cos x + i sin x. > The first example below follows this, the others not. > > Thanks for the education! > > > exp( complex(real = 0, imag = 2*pi) ) > [1] 1-0i > > exp( complex(real = pi, imag = 2*pi) ) > [1] 23.14069-0i > > exp( complex(real = pi/2, imag = 0) ) > [1] 4.810477+0i > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
