No, you have not. Take a look at expand.grid(rep(list(1:5), 2))
HTH, Jorge.- On Wed, Jan 25, 2012 at 12:10 PM, yan <> wrote: > thanks petr, > what if I got 200 elements, so I have to write expand.grid(x1=1, x2=1:2, > x3=1:3, x4=1:3, x5=1:3....x200=1:3))? > > Many thanks > > yan > > -- > View this message in context: > http://r.789695.n4.nabble.com/function-for-grouping-tp4324436p4327812.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
