Since you did not provide a sample of your data, here is an example of
how to take a vector and create a matrix with 5 entries for each
value, with the extra ones having a zero in the second column:
> x <- sample(1:7, 20, T)
> table(x)
x
1 2 3 4 5 6 7
2 4 3 2 4 4 1
> # create a matrix with 5 rows of each value in the vector 'x' with the extra
> rows
> # having 0 in the second column
> x.l <- lapply(split(x, x), function(.val){
+ # pad with at least 5 extra rows to make sure matrix is filled out
+ z <- cbind(c(.val, rep(.val[1],5)), c(rep(1, length(.val)), rep(0,5)))
+ z[1:5,] # only return the first 5
+ })
> # output the new matrix
> do.call(rbind, x.l)
[,1] [,2]
[1,] 1 1
[2,] 1 1
[3,] 1 0
[4,] 1 0
[5,] 1 0
[6,] 2 1
[7,] 2 1
[8,] 2 1
[9,] 2 1
[10,] 2 0
[11,] 3 1
[12,] 3 1
[13,] 3 1
[14,] 3 0
[15,] 3 0
[16,] 4 1
[17,] 4 1
[18,] 4 0
[19,] 4 0
[20,] 4 0
[21,] 5 1
[22,] 5 1
[23,] 5 1
[24,] 5 1
[25,] 5 0
[26,] 6 1
[27,] 6 1
[28,] 6 1
[29,] 6 1
[30,] 6 0
[31,] 7 1
[32,] 7 0
[33,] 7 0
[34,] 7 0
[35,] 7 0
>
On Thu, Mar 20, 2008 at 1:51 AM, Felix Zajitschek - UNSW
<[EMAIL PROTECTED]> wrote:
> Hi all,
>
> I have a dataset consisting of 5 columns and over 5000 rows. Each row
> gives information about an individual animal, including longevity, i.e.
> at what age an animal died.
> For the model I use I need to create n rows for each animal, n being its
> longevity, and a new column 'survival' with a binary 0/1 outcome. When
> an animal died e.g. at age 5, there have to be 5 rows of identical data,
> except 4 with 0 (=alive) for 'survival', and 1 row with '1' for
> 'survival'.
>
> I thought of creating matrices for each individual, adding first one
> column 'survival' containing zeros to the original dataset, then
> creating matrices with data = 'the vector containing all elements of an
> individual/row' ([1,], nrow = [a,b], exctracting the element for
> longevity, and then with byrow = TRUE letting the data be filled in by
> row. At the end I would have to set the last element in 'survival' to
> '1', and then combine all matrices into one single one.
>
> So far I've used Excel to create these datesets manually, but with more
> than 1000 individuals this gets really tedious. I haven't used R before
> for this sort of a bit more advanced data manipulation, and I would
> really appreciate any input/primer about how people would go about doing
> this.
>
> Thanks,
> Felix
>
>
> ______________________________________________________________
> ::Felix Zajitschek
> Evolution & Ecology Research Centre
> School of Biological, Earth and Environmental Sciences
> University of New South Wales - Sydney NSW 2052 - Australia
> Tel +61 (0)2 9385 8068
> Fax +61 (0)2 9385 1558
> eMail <mailto:[EMAIL PROTECTED]>
> [EMAIL PROTECTED]
>
> <http://www.bees.unsw.edu.au/school/researchstudents/zajitschekfelix.htm
> l> www.bees.unsw.edu.au/school/researchstudents/zajitschekfelix.html
>
>
> [[alternative HTML version deleted]]
>
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem you are trying to solve?
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