On Jan 5, 2012, at 17:04 , Christof Kluß wrote:
> Hi
>
> the output should look like r <- subset(tab, a==v)
> but now I have something like r <- subset(tab, "a"==v)
> and r <- subset(tab, [["a"]]==v)
> does not work :(
Presumably something with eval, bquote and as.name will work, but it's really
not a great idea to use subset() in a programming context (notice also that if
you accidentally have a variable tab$v, things might be much different than you
expect.) Consider Sarah's suggestion instead, possibly throwing in a !is.na().
>
> greetings
> Christof
>
> Am 05-01-2012 16:51, schrieb Christof Kluß:
>> Hi
>>
>> I want to do something like
>>
>> a <- c(10,20,15,43,76,41,25,46)
>> tab <- data.frame(a)
>>
>> name <- "a"
>>
>> for (v in unique(tab[[name]])) {
>> r <- subset(tab, name==v) # this does not work
>> ...
>> }
>>
>> i.e. a "string" on the left side of the select expression (subset). How
>> could I solve this?
>>
>> thx
>> Christof
>>
>
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--
Peter Dalgaard, Professor
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd....@cbs.dk Priv: pda...@gmail.com
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