drflxms wrote > > Jeff, > > thanks a lot for your quick reply and the hint! > > Meanwhile I found a solution that works - at least for my case ;) > The code to get the job done is > > df[order(match(df$level,desiredOrder)),] > > So we seem in need of one order statement more. I found this solution > doing it stepwise: > > ## sorting the levels of the level column in the data.frame > df$level <- factor(df$level,levels=desiredOrder) > ## sorting the data frame by the newly sorted level column > df[order(df$level),] > > Maybe this solution is of a help for someone else as well? > > But honestly I still do not exactly understand why > df[match(df$level,desiredOrder),] doesn't work... >
Read carefully ?match and then do match(df$level,desiredOrder) match(desiredOrder,df$level) and look carefully at the results. Then it should be clear. Berend -- View this message in context: http://r.789695.n4.nabble.com/sorting-a-data-frame-df-by-a-vector-which-is-not-contained-in-the-df-unexpected-behaviour-of-match-ar-tp4242326p4242400.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
