Oops. I guess I stopped reading about the fsep param when I saw PATH and
R_LIB because I'm not interested in those. I didn't get to the part I was
interested in. Thanks!
Ben
On Wed, Dec 28, 2011 at 5:33 PM, David Winsemius <dwinsem...@comcast.net>wrote:
>
> On Dec 28, 2011, at 5:57 PM, Ben quant wrote:
>
> One quick follow-up on reversing your example. Is there an easy way to get
>> the file.path separator for the platform? file.path("","") seems the be
>> the only way to do it.
>>
>
> I don't get it. Did you look at ?file.path ? It's default call shows fsep=
>
> > .Platform$file.sep
> [1] "/"
>
> ?.Platform
>
> --
> David.
>
>
>> So if filename is a valid file path, this will return the folders, drive,
>> and file name in vector form regardless of the platform:
>> folders = strsplit(normalizePath(**filename, winslash="/"), "/")[[1]]
>> This will undo the above regardless of the platform:
>> paste(folders,collapse=file.**path('"",""))
>>
>
>
>
>> Thanks again for your help Duncan!
>>
>> Ben
>>
>>
>> On Wed, Dec 28, 2011 at 2:37 PM, Duncan Murdoch <
>>> murdoch.dun...@gmail.com>**wrote:
>>>
>>> On 11-12-28 4:30 PM, Ben quant wrote:
>>>>
>>>> Hello, (sorry re-posting due to typo)
>>>>>
>>>>> I'm attempting to get the folders of a path in a robust way (platform
>>>>> independent, format independent). It has to run on Windows and Linux
>>>>> and
>>>>> tolerate different formats.
>>>>>
>>>>> For these: (The paths don't actually exist in Linux but you get the
>>>>> idea.)
>>>>>
>>>>> Windows:
>>>>> file_full_path = "C://Program Files//R//R-2.13.1//NEWS.pdf"
>>>>> file_full_path = "C:\Program Files\R\R-2.13.1\NEWS.pdf"
>>>>> Linux:
>>>>> file_full_path = "~/Program FilesR/R-2.13.1/NEWS.pdf"
>>>>> file_full_path = "/home/username/Program FilesR/R-2.13.1/NEWS.pdf"
>>>>>
>>>>> I would get for Windows: "C", "Program Files", "R",
>>>>> "R-2.13.1","NEWS.pdf"
>>>>> I would get for Linux: "home","username", "Program Files", "R",
>>>>> "R-2.13.1","NEWS.pdf"
>>>>> (The drive and/or home/username aren't necessary, but would be nice to
>>>>> have. Also, that file name isn't necessary, but would be nice.)
>>>>>
>>>>> Thank you for your help,
>>>>>
>>>>>
>>>>> If you use the normalizePath() function with winslash="/", then all
>>>> current platforms will return a path using "/" as the separator, so you
>>>> could do something like
>>>>
>>>> strsplit(normalizePath(****filename, winslash="/"), "/")[[1]]
>>>>
>>>>
>>>> You need to be careful with normalizePath: at least on Windows, it will
>>>> not necessarily do what you wanted if the filename doesn't exist.
>>>>
>>>> Duncan Murdoch
>>>>
>>>>
>>>
>>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________**________________
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>> PLEASE do read the posting guide http://www.R-project.org/**
>> posting-guide.html <http://www.R-project.org/posting-guide.html>
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
> David Winsemius, MD
> West Hartford, CT
>
>
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