Hello again.
I don't understand what didn't work.
First, it seems better to use 'nrow', the result is the same
stopifnot(length(x[,1]) == nrow(x))
Then your multiple OR condition.
#if((x[i,1] || x[i,2] || x[i,3] || x[i,4]) < 5)
x <- matrix(1:24, ncol=4)
for(i in 1:nrow(x))
if(any(x[i,] < 5))
cat("At least one is TRUE:", i, "\n")
for(i in 1:nrow(x))
if((x[i,1] < 5) | (x[i,2] < 5) | (x[i,3] < 5) | (x[i,4] < 5))
cat("The same with '|':", i, "\n")
In the second example each condition IS a condition. Unlike your original
"compound" one.
The 'Introduction to R' clearly states '|' as the union of the logical
expressions, The section is 2.4.
Also read Patrick's PDF, the parts I've read are great and very usefull.
(Thanks, Patrick, I was unaware of R inferno.pdf)
As a side note, you are duplicating the matrix 'a' assignement. Why not just
before the 'if'?
Then, you could simply test if any 'a' is less than 5.
for (i in 1: row(x))
{
a[1,1] <- x[i,1];
a[1,2] <- x[i,2];
a[2,1] <- x[i,3];
a[2,2] <- x[i,4];
if(any(a < 5))
{
etc...
(Or use the compound '|' ).
Rui Barradas
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