zoo:::na.approx will do nicely. Though you are going to have to supply some sort of time metric or it won't know where interpolations should happen.
Something like this is my usual route: x <- zoo(1:5, Sys.Date() + 2*(1:5)) x.new <- zoo(NA, seq(min(time(x)), to = max(time(x)), by = "day")) x.new[time(x)] <- x na.approx(x.new) Michael On Sat, Dec 24, 2011 at 5:39 PM, Alemtsehai Abate <abatea...@gmail.com> wrote: > Dear R users, > > I have two irregular time series say x and y. Each series is supposed to > cover 20 years. The data looks, for instance: > x<-c(200,178, 330, 127, 420) ## only 5 observations out of the expected 20 > annual values > y<-c(0.35,-0.18,-0.54,0.78,1.7,-1.1,0.2,1.9,0.49)### only 9 observations of > the expected 20 > > I need to intepolate each of the series into equally spaced 20 points. Is > there a function and library in R to do this please? > > Many thanks > > Tsegaye > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
