Dear Matt, Sarah and Rui,
To answer the original question for creating a symmetric matrix
>>> v<-c(0.33740, 0.26657, 0.23388, 0.23122, 0.21476, 0.20829, 0.20486,
>>> 0.19439, 0.19237,
>>> 0.18633, 0.17298, 0.17174, 0.16822, 0.16480, 0.15027)
z<-diag(6)
z[row(z) > col(z)] <- v
z <- z + t(z)
diag(z) <- 0
> z
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] 0.00000 0.33740 0.26657 0.23388 0.23122 0.21476
[2,] 0.33740 0.00000 0.20829 0.20486 0.19439 0.19237
[3,] 0.26657 0.20829 0.00000 0.18633 0.17298 0.17174
[4,] 0.23388 0.20486 0.18633 0.00000 0.16822 0.16480
[5,] 0.23122 0.19439 0.17298 0.16822 0.00000 0.15027
[6,] 0.21476 0.19237 0.17174 0.16480 0.15027 0.00000
Bill
On Dec 24, 2011, at 6:04 AM, Sarah Goslee wrote:
> Or the slightly shorter:
>
> z<-diag(6)
> z[row(z) > col(z)] <- v
>
> which is what lower.tri() does,
>
> and
> z <- diag(6)
> z[lower.tri(z)] <- v
>
> also works.
>
> Sarah
>
> On Fri, Dec 23, 2011 at 9:31 PM, Rui Barradas <ruipbarra...@sapo.pt> wrote:
>>
>> Matt Considine wrote
>>>
>>> Hi,
>>> I am trying to work with the output of the MINE analysis routine found at
>>> http://www.exploredata.net
>>>
>>> Specifically, I am trying to read the results into a matrix (ideally an
>>> n x n x 6 matrix, but I'll settle right now for getting one column into
>>> a matrix.)
>>>
>>> The problem I have is not knowing how to take what amounts to being one
>>> half of a symmetric matrix - excluding the diagonal - and getting it
>>> into a matrix. I have tried using "lower.tri" as found here
>>> https://stat.ethz.ch/pipermail/r-help/2008-September/174516.html
>>> but it appears to only partially fill in the matrix. My code and an
>>> example of the output is below. Can anyone point me to an example that
>>> shows how to create a matrix with this sort of input?
>>>
>>> Thank you in advance,
>>> Matt
>>>
>>> #v<-newx[,3]
>>> #or, for the sake of this example
>>> v<-c(0.33740, 0.26657, 0.23388, 0.23122, 0.21476, 0.20829, 0.20486,
>>> 0.19439, 0.19237,
>>> 0.18633, 0.17298, 0.17174, 0.16822, 0.16480, 0.15027)
>>> z<-diag(6)
>>> ind <- lower.tri(z)
>>> z[ind] <- t(v)[ind]
>>>
>>> z
>>> [,1] [,2] [,3] [,4] [,5] [,6]
>>> [1,] 1.00000 0.00000 0 0 0 0
>>> [2,] 0.26657 1.00000 0 0 0 0
>>> [3,] 0.23388 0.19237 1 0 0 0
>>> [4,] 0.23122 0.18633 NA 1 0 0
>>> [5,] 0.21476 0.17298 NA NA 1 0
>>> [6,] 0.20829 0.17174 NA NA NA 1
>>>
>>>
>> Hello,
>>
>> Aren't you complicating?
>>
>> In the last line of your code, why use 'v[ind]' if 'ind' indexes the matrix,
>> not the vector?
>>
>> z<-diag(6)
>> ind <- lower.tri(z)
>> z[ind] <- v #This works
>> z
>>
>> Rui Barradas
>>
>
> --
> Sarah Goslee
> http://www.functionaldiversity.org
>
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Professor http://personality-project.org
Department of Psychology http://www.wcas.northwestern.edu/psych/
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