This isn't a reproducible example, so I can't provide code,
but I would put all the y variables in a list and use lapply().
Sarah
On Mon, Dec 12, 2011 at 8:16 AM, Mintewab Bezabih
<mintewab.beza...@economics.gu.se> wrote:
> Dear R users,
>
> I am using the code below to generate a fitted value of b. I have about 300
> different values for for y (y1, y2, ...y300) which means I will have to write
> the code below 300 times to generate the 300 different fitted values for y.
> Is there a short way of doing that ?
>
> Many thanks in advance
> Mintewab
>
> library(mgcv)
> dat <- read.table("e:/minti's laptop/C/GBG/allround_survey/rainfallGPS.csv",
> header=T, sep=",")
> b<-gam(y1~s(x1, x2, k=100),data=dat)
> vis.gam(b)
> fitted(b)
--
Sarah Goslee
http://www.functionaldiversity.org
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