Re: [R] finding interpolated values along an empirical parametric curve

[Michael Friendly]

Thanks, John
That's very clever.  I didn't realize that the splines package supports 
multivariate regression
splines and that works well enough for my purposes; plus this solution 
is very transparent.

best,
-Michael


On 12/5/2011 9:50 AM, John Fox wrote:
Hi Michael,

I can get what appears to be a good interpolation with a regression spline
in a multivariate LM, playing around with the tuning parameter to leave 1
residual df. Try this:

library(splines)
mod<- lm(cbind(log.det, norm.beta) ~ bs(lambda, df=4), data=pd)
summary(mod)

x<- data.frame(lambda=seq(min(pd$lambda), max(pd$lambda), length=100))
fit<- predict(mod, newdata=x)
points(fit[, "norm.beta"], fit[, "log.det"], pch=16, cex=0.5)

x.2<- data.frame(lambda=c(lambda.HKB, lambda.LW))
fit.2<- predict(mod, x.2)
points(fit.2[, "norm.beta"], fit.2[, "log.det"], pch=15, col="green")

That doesn't solve the problem of calculating the normal, however.

I hope this helps,
  John

-----Original Message-----
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Michael Friendly
Sent: December-05-11 9:16 AM
To: R-help
Subject: [R] finding interpolated values along an empirical parametric
curve

Given the following data, I am plotting log.det ~ norm.beta, where the
points depend on a parameter, lambda (but there is no functional form).
I want to find the (x,y) positions along this curve corresponding to
two special values of lambda

lambda.HKB<- 0.004275357
lambda.LW<- 0.03229531

and draw reference lines at ~ -45 degrees (or normal to the curve) thru
these points.
How can I do this?  A complete example is below

  >  pd
        lambda   log.det norm.beta
0.000  0.000 -12.92710  3.806801
0.005  0.005 -14.41144  2.819460
0.010  0.010 -15.41069  2.423197
0.020  0.020 -16.82581  2.010924
0.040  0.040 -18.69819  1.611304
0.080  0.080 -21.05065  1.283928
  >

pd<-
structure(list(lambda = c(0, 0.005, 0.01, 0.02, 0.04, 0.08),
      log.det = c(-12.9270978142337, -14.411442487768, -
15.4106886674014,
      -16.8258120792945, -18.6981870228698, -21.050646106925),
      norm.beta = c(3.8068008759562, 2.81945995964196, 2.42319655878575,
      2.01092421747594, 1.6113040561427, 1.28392804825009)), .Names =
c("lambda", "log.det", "norm.beta"), class = "data.frame", row.names =
c("0.000", "0.005", "0.010", "0.020", "0.040", "0.080"))

clr<- c("black", rainbow(5, start=.6, end=.1)) lambdaf<-
c(expression(~widehat(beta)^OLS), ".005", ".01", ".02", ".04", ".08")
op<- par(mar=c(4, 4, 1, 1) + 0.2, xpd=TRUE) with(pd, {plot(norm.beta,
log.det, type="b",
      cex.lab=1.25, pch=16, cex=1.5, col=clr,
    xlab='shrinkage: ||b||',
      ylab='variance: log |(Var(b)|)')
      text(norm.beta, log.det, lambdaf, cex=1.25, pos=2)
      text(min(norm.beta), max(log.det), "Variance vs. Shrinkage",
cex=1.5, pos=4)
      })


# How to find the (x,y) positions for these values of lambda along the
curve of log.det ~ norm.beta ?
lambda.HKB<- 0.004275357
lambda.LW<- 0.03229531

--
Michael Friendly     Email: friendly AT yorku DOT ca
Professor, Psychology Dept.
York University      Voice: 416 736-5115 x66249 Fax: 416 736-5814
4700 Keele Street    Web:   http://www.datavis.ca
Toronto, ONT  M3J 1P3 CANADA

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--
Michael Friendly     Email: friendly AT yorku DOT ca
Professor, Psychology Dept.
York University      Voice: 416 736-5115 x66249 Fax: 416 736-5814
4700 Keele Street    Web:   http://www.datavis.ca
Toronto, ONT  M3J 1P3 CANADA

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.