On Dec 3, 2011, at 8:41 AM, syrvn wrote:
Hello,
imagine the following data.frame:
ID name
1 *_A
2 *_A
3 *_B
4 *_B
* = can be any pattern
I want to replace every row which ends with _A by 1 and every row
which ends
by _B with a 0
You can use grep(patt, x, value=TRUE) to return vlaues that can be
used in the prior answers to your earlier question today.
I would have worked it out and tested the strategy, but you continue
to fail to produce workable examples.... and then apologize that
people are "confused" by them. We are NOT confused... only annoyed ...
that you fail to use dput() or code for constructing workable code.
--
David.
so that the data.frame looks like the following:
ID name
1 1
2 1
3 0
4 0
Which function do I use best to achieve this?
Cheers,
Syrvn
--
View this message in context:
http://r.789695.n4.nabble.com/replace-values-tp4153301p4153301.html
Sent from the R help mailing list archive at Nabble.com.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
