AFAIK all solutions to the "grow object size" problem in R involve creation of
a new object to "change" an old one. There is considerable sophistication
under the hood that allows a minimum of intermediate objects to be created if
you are careful, but actually changing the size of an object in place is not
supported.
That doesn't mean that you have to "copy... to a temporary and then copy back",
since you can reference chunks of an existing object without actually moving
them in memory by using indexing. But (AFAIK) you cannot escape creating at
least one new copy of the data that "becomes" the object if you use rbind to
grow your object.
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Sent from my phone. Please excuse my brevity.
Sammy Zee <szee2...@gmail.com> wrote:
>Is there easy way (without copying the existing rows to a temporary
>location and copying back) to add a new row to a specific index
>location in
>an existing data frame?
>
>Example
>
>df = data.frame( A= c('a','b','c'), B=c(1,2,3), C=(10,20,30))
>
>newrow = c('X', 100, 200)
>
>I want to add the newrow as the second row to the data frame df
>
>Please suggest a solution that is efficient for a data frame that can
>have
>millions of rows, and I want to add a new row in any given index
>location
>of the data frame.
>
>Thanks,
>Sammy
>
> [[alternative HTML version deleted]]
>
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>and provide commented, minimal, self-contained, reproducible code.
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