Dear Community,

I am trying to write (update) a code for the following problem.
Lets assume we have a beta distribution.
I know one quantile, lets say, 10% of the mass lies above .8, that is between .8 and 1. In addition, I know that the average of this "truncated tail" is a given number, lets say .86. I have found the beta.select function in the LearnBayes package, which is as follows:

function (quantile1, quantile2)
{
    betaprior1 = function(K, x, p) {
        m.lo = 0
        m.hi = 1
        flag = 0
        while (flag == 0) {
            m0 = (m.lo + m.hi)/2
            p0 = pbeta(x, K * m0, K * (1 - m0))
            if (p0 < p)
                m.hi = m0
            else m.lo = m0
            if (abs(p0 - p) < 1e-04)
                flag = 1
        }
        return(m0)
    }
    p1 = quantile1$p
    x1 = quantile1$x
    p2 = quantile2$p
    x2 = quantile2$x
    logK = seq(-3, 8, length = 100)
    K = exp(logK)
    m = sapply(K, betaprior1, x1, p1)
    prob2 = pbeta(x2, K * m, K * (1 - m))
    ind = ((prob2 > 0) & (prob2 < 1))
    app = approx(prob2[ind], logK[ind], p2)
    K0 = exp(app$y)
    m0 = betaprior1(K0, x1, p1)
    return(round(K0 * c(m0, (1 - m0)), 2))
}

I assume one could change this code to get the results I need, but some parts of the function are not clear for me, any help would be greatly appreciated.

Thanks a lot:
Daniel

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to