On Nov 21, 2011, at 3:20 PM, Hao, Zhaozhe wrote:

Hi,

Thank you all for the the quick response. But there still some questions.

1) nTies = length(x) - length(unique(x)) cannot distinguish vector (1,2,2,2,3), and (1,2,2,3,3)....

2) table(x)[table(x) >1] tells me the right number, but how can I call the numbers from the result of table function? I.e., I want to get the tie number, t and use it in another equation.

This will give you a named one ros matrix, Can e address by location or name.

> x <- sample(c(1:10,NA,NA), 20, replace=TRUE)
> ties <- table(x)[table(x) >1]
>
> ties
x
1 2 3 4 5 8
2 3 2 2 2 3
> ties[1]
1
2
> ties["8"]    # note that this is really 3 and that the 8 is a name
8
3

> names(ties)
[1] "1" "2" "3" "4" "5" "8"
> unname(ties)
[1] 2 3 2 2 2 3



________________________________________
From: David Winsemius [dwinsem...@comcast.net]
Sent: Monday, November 21, 2011 14:05
To: Peter Langfelder
Cc: Hao, Zhaozhe; r-help@r-project.org
Subject: Re: [R] count ties after rank?

On Nov 21, 2011, at 2:50 PM, Peter Langfelder wrote:

On Mon, Nov 21, 2011 at 11:36 AM, Hao, Zhaozhe <haozhao...@ou.edu>
wrote:
Hello!

  I need to use Kruskal-Wallis test and post-hoc test (Dunn's
test) for my data. But when I searched around, I only found this
function: kruskal.test. But nothing for Dunn's test.

  So I started to write one myself.  But  I do not know how to
count ties in the data frame. I can use for loops but it seems long
and unnecessary since the rank function actually knows the ties. So
can anyone give me a hint on how I can "count" the number of ties?


If you just need the overall number of ties in a vector (say x), you
can get it by

nTies = length(x) - length(unique(x))

And if you wnat to know which ties are which you can do:

table(x)[table(x) > 1]


This will not work if missing data are present, so you will have to
remove those first.


table() would ignore missing data (assuming it were properly NA not-
valued).

x <- sample(c(1:10,NA,NA), 20, replace=TRUE)
table(x)[table(x) >1]
x
 1  4  7  9 10
 2  3  2  2  2
x
 [1]  7 10  3  9 NA NA  2  4 10 NA NA  4  5  9  6  4  1  1  7  8

--

David Winsemius, MD
West Hartford, CT


David Winsemius, MD
West Hartford, CT

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