will this work for you:
> str(x)
'data.frame': 10 obs. of 2 variables:
$ price : chr "0,00" "0,00" "0,02" "0,03" ...
$ mentioned: int 1 1 1 1 1 1 1 1 1 1
> # create vector with range of 'price'
> allPrices <- paste('0,', sprintf("%02d", 0:19), sep = '')
> # find missing prices and add with mentioned = 0
> newX <- rbind(x
+ , data.frame(price = setdiff(allPrices, x$price)
+ , mentioned = 0
+ , stringsAsFactors = FALSE
+ )
+ )
> newX[order(newX$price),]
price mentioned
1 0,00 1
2 0,00 1
11 0,01 0
3 0,02 1
4 0,03 1
5 0,03 1
6 0,04 1
12 0,05 0
13 0,06 0
14 0,07 0
15 0,08 0
16 0,09 0
7 0,10 1
17 0,11 0
18 0,12 0
19 0,13 0
20 0,14 0
21 0,15 0
8 0,16 1
22 0,17 0
23 0,18 0
9 0,19 1
10 0,19 1
>
On Fri, Nov 18, 2011 at 12:05 PM, Milan Bouchet-Valat <nalimi...@club.fr> wrote:
> Le vendredi 18 novembre 2011 à 15:06 +0000, Mario Giesel a écrit :
>> Hello, list,
>>
>> I've been struggling with this task for a while looking for an efficient way
>> to solve it:
>> There are two variables 'price' and 'mentioned'.
>> I want to 'enlarge' data so that missing price points within the price range
>> are added to variable price.
>> Also variable 'mentioned' is to receive values 0 in these cases.
>> Note: Price points in original data can repeat if several persons mentioned
>> that price point.
> Let's say prices1 holds the first list of prices, prices2 the
> supplementary one. Try:
> prices <- c(prices1, prices2)
> prices <- sort(prices[!duplicated(prices)])
> data.frame(price=prices, mentioned=prices %in% prices1)
>
> Regards
>
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>
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
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