I have a set of character vectors of uneven length that I have stored in a list. I can easily enough get any column of them using lapply but what I want is to be able to create a matrix of them. Other than some kind of brute force looping approach I have drawn a blank.
Would somebody please suggest something? Thanks Example. mylist <- list(aa=c("cat","peach" ), bb=c("dog", "apple", "iron"), cc = c("rabbit", "orange", "zinc", "silk")) myfun <- function(dff) dff[1] vect1 <- unlist(lapply(mylist, myfun)) Looking for the perfect gift? Give the gift of Flickr! ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.