On 02/11/11 11:14, Ernest Adrogué wrote:
Hi,
On ocasion, you need to subscript an array that has an arbitrary
(ie. not known in advance) number of dimensions. How do you deal with
these situations?
It appears that it is not possible use a list as an index, for
instance this fails:
x<- array(NA, c(2,2,2))
x[list(TRUE,TRUE,2)]
Error in x[list(TRUE, TRUE, 2)] : invalid subscript type 'list'
The only way I know is using do.call() but it's rather ugly. There
must be a better way!!
do.call('[', c(list(x), TRUE, TRUE, 2))
[,1] [,2]
[1,] NA NA
[2,] NA NA
Any idea?
It's possible that matrix subscripting might help you. E.g.:
a <- array(1:60,dim=c(3,4,5))
m <- matrix(c(1,1,1,2,2,2,3,4,5,1,2,5),byrow=TRUE,ncol=3)
a[m]
[1] 1 17 60 52
You can build "m" to have the same number of columns as your array
has dimensions.
It's not clear to me what result you want in your example.
cheers,
Rolf Turner
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