On Wed, 12 Mar 2008, Dwayne Blind wrote:
> Dear R users,
>
> I wrote the following toy example to explain my problem :
>
> a=0
> f=function(x,y,z) {
> if (a==0) x[1]+x[2]+y
> if (a!=0) x[1]+x[2]+y+z
> }
> f(1:2,3)
>
>
> I have not specified z and I get an error.
What was the error? It works for me (so I've no idea), and returns NULL,
the value of the last expression (invisibly). I think you intended
f <- function(x, y, z) if (a==0) x[1]+x[2]+y else x[1]+x[2]+y+z
or
f <- function(x, y, z) ifelse(a==0, x[1]+x[2]+y, x[1]+x[2]+y+z)
> Although a=0, R seems to want to
> know z because it's in the expression x[1]+x[2]+y+z.
>
> So I tried to put a default value :
>
> a=0
> f=function(x,y,z=0) {
> if (a==0) x[1]+x[2]+y
> if (a!=0) x[1]+x[2]+y+z
> }
> f(1:2,3)
>
> Why isn't it working ? Sometimes everything is fine even though a parameter
> is not specified.
>
> Thanks a lot.
>
> [[alternative HTML version deleted]]
>
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Brian D. Ripley, [EMAIL PROTECTED]
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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