On Oct 17, 2011, at 9:45 PM, David Wolfskill wrote:

Sorry about the odd terminology, but I suspect that my intent might be
completely missed had I used "aggregate" or "classify" (each of which
appears to have some rather special meanings in statistical analysis and
modeling).

I have some data about software builds; one of the characteristics of
each is the name of the branch.

A colleague has generated some fairly interesting graphs from the data,
but he's treating each unique branch as if it were a separate factor.

Last I checked, I had 276 unique branches, but these could be
aggregated, classified, or "lumped" into about 8 - 10 categories; I
believe it would be useful and helpful for me to be able to do precisely
that.

A facility that could work for this purpose (that that we use in our
"continuous build" driver) is the Bourne shell "case" statement. Such a
construct might look like:

        case branch in
        trunk)    factor="trunk"; continue;;
        IB*)      factor="IB"; continue;;
        DEV*)     factor="DEV"; continue;;
        PVT*)     factor="PVT"; continue;;
        RELEASE*) factor="RELEASE"; continue;;
        *)        factor="UNK"; continue;;
        esac

Which would assign one of 6 values to "factor" depending on the value of
"branch" -- using "UNK" as a default if nothing else matched.

Mind, the patterns there are "Shell Patterns" ("globs"), not regular
expressions.

I've looked at R functions match(), pmatch(), charmatch(), and switch();
while each looks as it it might be coercable to get the result I want,
it also looks to require iteration over the thousands of entries I have
-- as well as using the functions in question in a fairly "unnatural"
way.

I could also write my own function that iterates over the entries,
generating factors from the branch names -- but I can't help but think
that what I'm trying to do can't be so uncommon that someone hasn't
already written a function to do what I'm trying to do. And I'd really
rather avoid "re-inventing the wheel," here.

Here's a loopless lumping of random letters with an "other" value . There better ways, but my efforts with match and switch came to naught. "pmatch" returns a numeric vector that selects the group.

> x <- sample(letters[1:10], 50, replace =TRUE)
> c("abc","abc","abc","def","def","def","ghi","ghi","ghi", "j") [pmatch(x, letters[1:10], duplicates.ok=TRUE, nomatch=10)] [1] "ghi" "ghi" "ghi" "ghi" "ghi" "def" "def" "ghi" "def" "abc" "abc" "j" "def" "def" "ghi" [16] "abc" "j" "def" "ghi" "abc" "ghi" "abc" "abc" "abc" "abc" "abc" "abc" "ghi" "def" "abc" [31] "ghi" "def" "ghi" "def" "abc" "ghi" "ghi" "j" "abc" "def" "abc" "ghi" "abc" "def" "def"
[46] "def" "j"   "ghi" "def" "def"

Classifying 5 million letters in about a second:

> x <- sample(letters[1:10], 5000000, replace =TRUE)
> system.time( v <- c("abc","abc","abc","def","def","def","ghi","ghi","ghi", "j") [pmatch(x, letters[1:10], duplicates.ok=TRUE, nomatch=10)] )
   user  system elapsed
  0.858   0.208   1.062

The same strategy (indexing to return a set membership) can be used with findInterval.

--

David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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