On Oct 14, 2011, at 9:26 AM, Weidong Gu wrote:
It would be nice if you could provide a sample.
That is certainly true.
However, if the data
in the list have the same colnames, you can combine them by
df<-do.call('rbind',your_list_data_frame)
Then you can do what you want on the dataframe instead of a list
HTH
Weidong Gu
On Fri, Oct 14, 2011 at 9:06 AM, Juliet Ndukum <jpnts...@yahoo.com>
wrote:
I have a list of dataframes i.e. each list element is a dataframe
with three columns and differing number of rows. The third column
takes on only two values. I wish to split the list into two
sublists based on the value of the third column of the list element.
Perhaps something like:
list_of_firsts <- lapply(dflist, function(x) X[ , X[,3]=="first"] )
list_of_seconds <- lapply( dflist, function(x) X[ , X[,3]=="second"])
Ow with subset (but without that missing example it is more difficult
to show the true value of subset:
subset(X, select= X[,3]=="first")
Second issue with lists as well. I would like to reduce each of the
sublist based on the range of the second column, i.e. if the range
of the second column is greater than twenty for example keep the
list element.
Same as above with an inequality sign.
Could someone help me with a code to implement these two issues.
Thanks in advance for your help,
JN
[[alternative HTML version deleted]]
David Winsemius, MD
West Hartford, CT
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