Dear Johnny,
this is a bug in the hashing-code of sets. Use:
sets_options("hash", FALSE)
lset <- cset(s, matchfun = matchfun(match.2.list))
which will work.
Thanks for pointing this out!
David
----------------
Hi,
I tried to use the sets package yesterday, which seems to be a very
powerful
package: thanks to the developers. I wanted to define sets of lists where 2
lists are considered equal if they have the same length.
So, I implemented:
match.2.list <- function(l1,l2){
length(l1)==length(l2)
}
and then defined my cset as:
s <- set(list(1,2),list(3,4))
lset <- cset(s,matchfun(match.2.list))
so if I now do:
y <- list(3,4)
y %e% lset
I get the correct answer, which is TRUE.
But if I do:
x <- list(1,8)
x %e% lset
I now get FALSE, even though x is a list of length 2, and should thus match
any of the 2 lists in lset.
I must be doing something wrong; I checked with the doc, but I don't
understand.
--
Priv.-Doz. Dr. David Meyer
Institut für Wirtschaftsinformatik
Fachhochschule Technikum Wien
Höchstädtplatz 5, 1200 Wien
T: +43 1 333 40 77-394
F: +43 1 333 40 77-99 394
E: david.me...@technikum-wien.at
I: www.technikum-wien.at
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