I have a list of data frames like the following: set.seed(123) a<- data.frame(x=runif(10), y = runif(10), sample = seq(1,10)) b<- data.frame(x=runif(10), y = runif(10), sample = seq(1,10)) L<- list(a,b)
All data frames in the list have the same dimensions. I need to calculate the sample means for x and y. The real data are lists of several thousand quite large dataframes, so I need something that is pretty fast. Here is what I have so far: y<- rowMeans(sapply(L,'[[','y')) x<- rowMeans(sapply(L,'[[','x')) this works great, but I'm only able to get the sample means for one column at a time. Is there a way to automate things a bit so that I can get the sample means for several columns with one call? Thanks for any suggestions, Matthew [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.