On Mon, 19 Sep 2011, Achim Zeileis wrote:
This should do what you want, I think:
R> z <- zoo(matrix(1:8, ncol = 2), Sys.Date() + 0:3)
R> z[2,2] <- NA
R> z[3,] <- NA
R> z
2011-09-19 1 5
2011-09-20 2 NA
2011-09-21 NA NA
2011-09-22 4 8
R> z[!apply(is.na(z), 1, all),]
2011-09-19 1 5
2011-09-20 2 NA
2011-09-22 4 8
Z,
I'm quite new to R so I have a lot to learn even reading all I can, so I
ask your patience.
Do I mis-read the above that it applies to a matrix but not a data.frame?
Rich
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