On 16.09.2011 17:43, Chris82 wrote:
Dear R users,
I guess, I have a quit simple problem, but I'm not getting the solution.
I create a matrix like this:
test<- matrix(seq(1,3,1),ncol=5,nrow=3)
then I want to create one vector, consisting of every row of the matrix.
My first idea was to do this with a for loop.
op<- vector()
for (o in 1:3){
op[o]<- as.vector(test.id[o,])
}
A matrix is a vector with dim attributes, hence you can simply transpose
and strip all the attributes:
as.vector(t(test))
Uwe Ligges
The results should be like this:
[1] 1 1 1 1 1 2 2 2 2 2 2 3 3 3 3 3
thanks!
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