On Sep 8, 2011, at 3:35 PM, Alexander Engelhardt wrote:
Am 08.09.2011 20:48, schrieb Marc Schwartz:
> There was a post from Martin Maechler some years ago and I had to
search a bit to find it. For these sorts of issues, I typically
trust his judgement.
>
> The post is here:
>
> https://stat.ethz.ch/pipermail/r-help/2003-April/032471.html
>
> His solution also handles complex numbers.
For those too lazy to follow
He is basically creating the function is.whole:
is.whole <- function(x)
is.numeric(x) && floor(x)==x
Are you sure? I thought the test would have been all.equal(x, round(x,
0) )
My reasoning was that 1.999999999999 should be considered 2 but floor
would make it 1.
> x=1.999999999999
> x
[1] 2
> floor(x)
[1] 1
> isTRUE(all.equal(x, floor(x)))
[1] FALSE
> all.equal(x, round(x,0))
[1] TRUE
Seems like the most appropriate way now. I'll make it so!
Thanks for your help :-)
-- Alex
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