On Thu, Sep 1, 2011 at 8:10 AM, . . <xkzi...@gmail.com> wrote: > Why time is increasing for the same operation? > > I was expecting +/- the same time for each n. > > Thanks in advance. > > bench <- function(f1, n, ...) { > t <- 0 > for(i in 1:n) { > func <- function(x) x^2 > expr <- list(...)[1] > f1 <- c("system.time(y <- ", gsub("XXX",expr,f1),")[3]") > t1 <- eval(parse(text = f1)) > printf("time %d: %f\n", i, t1) > t <- t + t1 > } > t <- t/n > printf("mean time: %f", t) > } > bench("func(XXX)", 10, "1:100") >
On each iteration f1 gets larger. (Also printf is not defined.) Check out the rbenchmark package. -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.